At a given temperature the vapor pressures of hexane and octane are 183 mmhg and 59.2 mmhg, respectively. calculate the total vapor pressure over a solution of haxane and octane with xhexane = 0.580.

Total vapor pressure can be calculated using partial vapor pressures and mole fraction as follows:

Here, is mole fraction of A, is mole fraction of B, is partial pressure of A and is partial pressure of B.

The mole fraction of A and B are related to each other as follows:

In this problem, A is hexane and B is octane, mole fraction of hexane is given 0.580 thus, mole fraction of octane can be calculated as follows:

Partial pressure of hexane and octane is given 183 mmHg and 59.2 mmHg respectively.

Now, vapor pressure can be calculated as follows:

Putting the values,

Therefore, total vapor pressure over the solution of hexane and octane is 131 mmHg.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

2b2t

explanation:

2b2t