Balanced equation showing the combustion of methane. do not forget to include the states of matter of the reactants and the products. hint: methane is a gas at standard temperature and pressure 2. to begin the experiment, a bomb calorimeter is filled with 4 1.11 g ch and an excess of oxygen. the heat capacity of the calorimeter, including the bomb and the water, is 4.319 kj g c⋅° . the initial temperature of the system was 24.85°c, and the final temperature was 35.65°c. calculate the change in temperature, ∆τ. 3. using the formula ∆ =− ⋅ ⋅∆ h mc t , calculate the heat of combustion of 4 1.11 g ch . 4. evaluate the information contained in this calculation and complete the following sentence: this calculation shows that burning grams of methane [takes in/gives off] energy. 5. the molecular mass of methane is 16.4 g. calculate the number of moles of methane burned in the experiment. 6. what is the experimental molar heat of combustion? 7. the accepted value for the heat of combustion of methane is 890 kj/mol. explain why the experimental data might differ from the theoretical value. 8. given the formula theoretical value experimental value % error = 100 theoretical value− experimental value/theoretical⋅ , calculate the percent error for the experiment.

An atom of sodium-23 (atomic number = 11) has a positive charge of +1. give this information, how many electrons does it have? how many proteins and neutrons does this atom have

Design techniques and materials that reduce the negative environmental impact of a structure are referred to as

Predict the products of the following acid-base reactions, and predict whether the equilibrium lies to the left or to the right of the reaction arrow.part ao2-(aq)+h2o(l)< => express your answer as part of a chemical equation. identify all of the phases in your answer.o2-(aq)+h2o(l) < => oh-(aq)+oh-(aq)part bpredict whether the equilibrium lies to the left or to the right of the equation in previous part.h2o is a stronger acid than oh–, so the equilibrium lies to the right.h2o is a weaker acid than oh–, so the equilibrium lies to the left.h2o is a stronger acid than oh–, so the equilibrium lies to the left.h2o is a weaker acid than oh–, so the equilibrium lies to the right.part cch3cooh(aq)+hs? (aq) < => express your answer as part of a chemical equation. identify all of the phases in your answer.ch3cooh(aq)+hs-(aq) < => h2s(aq)+c2h3o2-(aq)h2s(aq)+c2h3o2-(aq)part dpredict whether the equilibrium lies to the left or to the right of the equation in previous part.ch3cooh is a weaker acid than h2s, so the equilibrium lies to the right.ch3cooh is a weaker acid than h2s, so the equilibrium lies to the left.ch3cooh is a stronger acid than h2s, so the equilibrium lies to the right.ch3cooh is a stronger acid than h2s, so the equilibrium lies to the left.part eno2-(aq)+h2o(l) < => express your answer as part of a chemical equation. identify all of the phases in your answer.no2-(aq)+h2o(l) < => part fpredict whether the equilibrium lies to the left or to the right of the equation in previous part.hno2 is a stronger acid than h2o, so the equilibrium lies to the right.hno2 is a weaker acid than h2o, so the equilibrium lies to the left.hno2 is a stronger acid than h2o, so the equilibrium lies to the left.hno2 is a weaker acid than h2o, so the equilibrium lies to the right.