Chemistry, 10.07.2019 03:30 suemmimonjaras8374

Consider a new temperature scale (ºa) based on the melting and boiling points of ammonia (nh3) which are taken as 0.0 ºa and 100.0 ºa, respectively. on the celsius scale ammonia melts at –77.7 ºc and boils at –33.3 ºc. find the temperature in ºa that corresponds to 25.0 ºc

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Answer from: demetriascott20

- 25.0 degree C corresponds to 231 ^0A .

Solution:- Let's say the two temperature scales have linear relationship. The equation of line is:

y=mx+c

where, m is the slope of the line and c is the intercept. Let's take the new temperature scale, ^0A for y and ^0C as . The equation would be looking as:

^0A=m*^0C+c

melting point of ammonia in new scale is 0.0 ^0A and in celsius scale it is -77.7 degree C. Boiling point in new scale is 100.0 ^0A and in celsius scale it is -33.3 degree C.

Let's plug in the values in the equation of line for melting points and boiling points to make two equations that we would solve:

For melting point:- 0.0=m(-77.7)+c

For boiling point:- 100=m(-33.3)+c

Now, we solve these two equations to find out the slope of the equation that is the value of m. Let's multiply the second equation by negative means changing all the signs from negative to positive and vice versa.

0.0=m(-77.7)+c

-100=m(+33.3)-c

---------------------------------------------

-100=-44.4m

$m=\frac{-100}{-44.4}$

m=2.25

Let's plug in this value of m in any of the two equations we have for melting point and boiling points to find out the value of intercept, c.

Let's say we use 0.0=m(-77.7)+c equation.

0.0=2.25(-77.7)+c

0.0=-174.825+c

c=174.825

Now, the first equation, ^0A=m*^0C+c could be written as:

^0A=2.25*^0C+174.825

We use this equation to convert the temperature of one scale to another.

We are asked to find the temperature in ^0A that corresponds to 25.0 ^0C .

Let's plug in the value of this degree C temperature in the above equation:

^0A=2.25(25.0)+174.825

= ^0A=56.25+174.825

= ^0A=231.075

This could be round to 231.

So, 25.0 degree C corresponds to 231 ^0A .

Answer from: Quest

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Answer from: Quest

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.

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