Raw one valid lewis structure (including all lone pair electrons and any formal charges) for ch2n2. assume the atoms are arranged as shown below. h c n n h

In the trial structure (1st image below), every atom has an octet.

Valence electrons = 20

Valence electrons available = 4 + 2 +10 = 16

The trial structure has 4 electrons too many. The actual structure must have two double bonds or one triple bond.

The second image shows two possible Lewis structures.

Answerthe heat seperates the molecules making the powder dissolve quicker

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