50 grams of propane is placed into a bomb calorimeter at 20 deg c. it is found that the heat released is 50 kj. what is the temperature of the system? the heat capacity of the cariometer is 6.00 kj/c

The final temperature is 28 °C.

There are two heat transfers involved.

heat from combustion of propane + heat gained by water = 0

q_1 + q_2 = 0

q_1+ C_calΔT = 0

q_1 = -50 kJ

q_2 = 6.00 kJ·°C^(-1)  × ΔT = 6.00 ΔT kJ·°C^(-1)

q_1 + q_2 = -50 kJ + 6.00 ΔT kJ·°C^(-1) = 0

ΔT = 50/[6.00 °C^(-1)] = 8.33 °C

T_f = T_i + ΔT = 20 °C + 8.33 °C = 28 °C

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.