Arectangular piece of aluminum foil measures 13.72 cm x 8.63 cm and has a mass of 3.1 g. find how thick it is

The two dimensions of aluminum foil are given 13.72 cm and 8.63 cm respectively with mass  3.1 g.

The density of aluminum is . It is defined as mass per unit volume thus, volume of aluminum can be calculated as follows:

Putting the values.

The volume of cuboid is , the length and breadth are given, height can be calculated as follows;

Putting the values,

Or, approximately 9.7\times 10^{-3}cm

Therefore, thickness of aluminum foil is

answer; protein;

- lead + phosphoric acid = hydrogen + lead(ii) phosphate