Chemistry, 10.07.2019 18:00 yasminlockser6

When 15 grams of wood burns completely in 25 grams of oxygen, 20 grams of water vapor and some carbon dioxide are given off. a. identify each of the reactant(s) and the product(s). b. how many grams of carbon dioxide would be produced in this example? c. what is the name of the law that you need to determine your answer for b?

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Answer from: Neko1kat

Answer :

The correct answer for A . Reactant = woods and oxygen ,

Products = water vapor + carbon dioxide

B. Mass of carbon dioxide = 20 g

C. Law of Conservation of Mass .

Given : Mass of wood = 15 g Mass of oxygen = 25 g

Mass of water Vapor = 20 g

A. To identify the reactant and products

Reactants : These are starting material of chemical reaction . They undergo chemical change by breaking bond and forms new bonds to form the products.

Products : These are substances which are formed in a chemical reaction when new bonds are formed .

In question following reaction take place :

Woods + Oxygen → Carbon dioxide + water vapor

Since woods are burning in presence of oxygen means bonds are breaking in them . Hence Woods and oxygen are REACTANTS

While Carbon dioxide and water vapor are produced in the reaction , they are known as PRODUCTS

B. To find mass of Carbon dioxide :

Mass of carbon dioxide can be calculated using Law of conservation of mass .

The law states "" Mass is neither destroyed nor created in an chemical reaction . Or Mass of elements before reaction is equal to mass of elements after the reaction . ""

Hence ., it can be said :

Sum of mass reactants = sum of mass of products

Mass of reactants = Mass of Woods + mass of oxygen = 15 g + 25 g = 40 g

Mass of reactant = mass of product = 40 g

Mass of products = mass of carbon dioxide + mass of water vapor

40 g = mass of Carbon dioxide + 20 g

Mass of Carbon dioxide = 20 g

C. To identify the law .

As already discussed in part B. the law is " Law of Conservation of Mass " .

Answer from: Quest

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.

Answer from: Quest

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