How to calculate the mass of iron in .275 grams of iron iii sulfate?

Molar mass of iron(III)sulfate that is Fe₂(SO₄)₃ =399.88 g mol⁻¹  

Mass given of  iron(III)sulfate that is Fe₂(SO₄)₃= 0.275 g

Number of moles of iron(III)sulfate that is Fe₂(SO₄)₃=  

                                                                                  =0.00068 mol

there are two moles of Fe in 1 mole of Fe₂(SO₄)₃

So, in 0.00068 mol of Fe₂(SO₄)₃=2 ×0.00068 mol of Fe

                                                  = 0.00136 mol of Fe

molar mass of Fe=55.8 g mol⁻¹

So the mass of iron in 0.00136 mol of Fe= 55.8 g mol⁻¹ × 0.00136 mol

                                                                  =0.075 g

Mass of iron  =

The chemical formula of iron (III) sulfate =

First, calculate the number of moles of

Number of moles of iron (III) sulfate =

Molar mass of iron (III) sulfate = 399.88 g/mol

Number of moles of iron (III) sulfate  =

=

In one mole of iron (III) sulfate there are two moles of iron according to the chemical formula.

So, in of iron (III) sulfate there are = of iron.

Number of moles of iron  =

Molar mass of iron  =

Mass of iron  =

=

=

=

Hence, mass of iron =

here's the link to your question!

explanation:

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates