A425.00-gram sample of a compound decomposes into 196.01 grams of carbon, 41.14 grams of hydrogen, 130.56 grams of oxygen, and 57.29 grams of silicon. experiments have shown the compound has a molecular weight of 208.329. what is the molecular formula? a. c8h5o2si b. c2h5osi c. c4h10o2si d. c8h20o4si

The molecular formula is D. C_8H_20O_4Si.

Step 1.Calculate the empirical formula

a)Calculate the moles of each element

Moles of C= 196.01 g C × (1 mol C/12.01 g C) = 16.325 mol C  

Moles of H = 41.14 g H × (1 mol H/1.008 g H) = 40.813 mol H

Moles of O = 130.56 g O × (1 mol O/16.00 g O) = 8.1650 mol O

Moles of Si = 57.29 g Si × (1 mol Si/28.085 g Si) = 2.0399 mol Si

b)Calculate the molar ratio of each element

Divide each number by the smallest number of moles and round off to an integer

C:H:O:Si = 8.0027:20.008:4.0027:1 ≈ 8:20:4:1

c)Write the empirical formula

EF = C_8H_20O_4Si

Step 2. Calculate the molecular formula

EF Mass = 208.33 u

MF mass = 208.329  u

MF = (EF)_n

n = MF Mass/EF Mass = 208.329 u/208.33 u = 1.0000 ≈ 1

MF = C_8H_20O_4Si

the correct answer is:

a. formation of precipitation