How many moles of copper are present in a sample of tennantite with a mass of 2370 grams

19.224 moles of copper are present in a sample of tennantite with a mass of 2370 grams.

Explanation:

The tennantite is a mineral of copper, arsenic, and sulfur.

The ideal chemical formula of tennantite  =

Given :

The sample of 2,370 grams of tennantite.

To find:

The number of moles of copper in 2370 grams of tennantite.

Solution:

The mass of tennantite = 2,370 g

The molar mass of tennantite  :

The moles of tennantite :

In 1 mole of tennantite,  there are 12 moles of copper, then in 1.602 moles of tennantite there will be:

19.224 moles of copper are present in a sample of tennantite with a mass of 2370 grams.

Learn more about the moles of substance here:

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A sample of tennantite with mass of 2370 g contains 19.23 mol Cu.

You must make the following conversions:

Mass of tennantite → moles of tennantite → moles of Cu

Step 1. Calculate the moles of tennantite (Tn)

The ideal chemical formula of Tn is Cu_12As_4S_13.

Molar mass = (12×63.55 + 4×74.92 + 13×32.06) g/mol

= (762.60 + 299.68 + 416.78) g/mol = 1479.06 g/mol

Moles of Tn = 2370 g Tn × (1 mol Tn/1479.06 g Tn) = 1.60 24 mol Tn

Step 2. Calculate the moles of Cu

Moles of Cu = 1.6024 mol Tn × (12 mol Cu/1 mol Tn) = 19.23 mol Cu

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