Given 8.40 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?

               11.07 g of CH₃CH₂CH₂COOC₂H₅

Solution:

The Balance Chemical Equation is as follow,

        CH₃CH₂CH₂COOH + C₂H₅OH    →    CH₃CH₂CH₂COOC₂H₅  +  H₂O

According to equation,

  88.11 g (1 mol) Butanoic Acid produces  =  116.16 g (1 mol) of Ethyl Butyrate

So,

         8.40 g Butanoic Acid will produce  =  X g of Butyric Acid

Solving for X,

                      X  =  (8.40 g × 116.16 g) ÷ 88.11 g

                      X  =  11.07 g of Ethyl Butyrate

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