If an automobile travels 225 mi with a gas mileage of 21.5 mi/gal , how many kilograms of co2 are produced? assume that the gasoline is composed of octane, c8h18(l), whose density is 0.69 g/ml.

- 84.2 kg of carbon dioxide.

Solution:- Distance and car mileage are given from which we could calculate the fuel required to cover the given distance. With the help of the given fuel density and fuel calculated volume the mass of fuel that is octane could be calculated. Some unit conversions are also done here. After this by writing balanced combustion equation and using stoichiometry the amount of carbon dioxide produced could easily be calculated.

The calculations are shown below:

= 27331.22 g of octane

The balanced equation for the combustion of Octane is:

We will use dimensional analysis here also to solve for mass of carbon dioxide formed. Grams of octane are converted to moles and then using mole ratio the moles of carbon dioxide are calculated. Moles are converted to grams on multiplying by molar mass and then finally the grams are converted to kilograms as:

=

So, 84.2 kg of carbon dioxide would be produced by an automobile.

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.

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d.) gravity pulled particles of dust and gas together to form planets.