The mole fraction of he in a gaseous solution prepared from 4.0 g of he, 6.5 g of ar, and 10.0 g of ne is

Given that there is 4.0 g of He, 6.5 g of Ar, and 10.0 g of Ne :

So, first all these masses are converted into moles:

Total Number of moles  = 1 + 0.1627 + 0.4955 = 1.658 mol

                                                = 

just did the assignment and the answer was #1 +2 n

can you list the answers so i can answer