If 32.78 ml of naoh solution is required to neutralize 20.00 ml 0f 0.2500 m of sulfuric acid, h2so4(aq), what is the concentration of the naoh solution? the balanced equation is: 2naoh(aq) + h2so4(aq) → na2so4(aq) + 2h2o(l)

The  concentration of the NaOH solution is 0.3051 mol/L.

Step 1. Calculate the moles of H_2SO_4

Moles of H_2SO_4

= 20.00 mL H_2SO_4 × (0.2500 mmol H_2SO_4/1 mL H_2SO_4)

= 5.000 mmol H_2SO_4

Step 2. Calculate the moles of NaOH

Moles of NaOH = 5.000 mmol H_2SO_4× (2 mmol NaOH /1 mmol H_2SO_4)

= 10.00 mmol NaOH

Step 3. Calculate the concentration of the NaOH

c = moles/litres = 10.00 mmol/32.78 mL = 0.3051 mol/L

i'm assuming that it's c.) red bank..