The force of attraction between a divalent cation and a divalent anion is 1.49 x 10-8 n. if the ionic radius of the cation is 0.096 nm, what is the anion radius?

The attractive force between two isolated ions is given by the formula:

 -(1)

where,

is force of attraction, is permittivity of vacuum = , and are valence of two ions, is the electron charge = and is the inter-atomic distance.

The inter-atomic distance,

where, is the radius of cation and is the radius of anion.

Since value of radius of cation is given so,

  -(2)

The cation and anion are divalent so the value of and is 2 and -2 of cation and anion respectively.

Substituting the values in formula (1):

=

Substituting this value of in equation 2:

Hence, the radius of anion is .

i'm pretty sure its b i might be wrong though!