Write a balanced equation to show the reaction of sulfurous acid with lithium hydroxide to form water and lithium sulfite. write a balanced equation to show the reaction of sulfurous acid with lithium hydroxide to form water and lithium sulfite. h2s (aq) + 2 lioh (aq) → 2 h2o (l) + li2s (aq) hso3 (aq) + lioh (aq) → h2o (l) + liso3 (aq) h2so4 (aq) + lioh (aq) → h2o (l) + li2so4 (aq) hso4 (aq) + lioh (aq) → h2o (l) + liso4 (aq) h2so3 (aq) + 2 lioh (aq) → 2 h2o (l) + li2so3 (aq)

H_2SO_3(aq) + 2LiOH(aq) → Li_2SO_3(aq) + 2H_2O(ℓ)

Step 1. Write the unbalanced equation

H_2SO_3(aq) + LiOH(aq) → Li_2SO_3(aq) + H_2O(ℓ)

Step 2. Balance the equation

H_2SO_3(aq) + 2LiOH(aq) → Li_2SO_3(aq) + 2H_2O(ℓ)

oh it is true if thats what you are asking

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3