First-order reaction that results in the destruction of a pollutant has a rate constant of 0.l/day. (a) how many days will it take for 90% of the chemical to be destroyed? (b) how long will it take for 99% of the chemical to be destroyed? (c) how long will it take for 99.9% of the chemical to be destroyed?

Rate equation for first order reaction is as follows:

Here, k is rate constant of the reaction, t is time of the reaction, is initial concentration and is concentration at time t.

The rate constant of the reaction is .

(a) Let the initial concentration be 100, If 90% of the chemical is destroyed, the chemical present at time t will be 100-90=10, on putting the values,

Thus, time required to destroy 90% of the chemical is 23.03 days.

(b) Let the initial concentration be 100, If 99% of the chemical is destroyed, the chemical present at time t will be 100-99=1, on putting the values,

Thus, time required to destroy 99% of the chemical is 46.06 days.

(c)  Let the initial concentration be 100, If 99.9% of the chemical is destroyed, the chemical present at time t will be 100-99.9=0.1, on putting the values,

Thus, time required to destroy 99.9% of the chemical is 69.09 days.

answer; protein;

the answer is na (sodium)