How many liters of fluorine gas can react with 32.0 grams of sodium metal at standard temperature and pressure? show all of the work used to find your answer. 2na + f2 yields 2naf?

            15.58 L of F₂

Solution:

The Balance Chemical equation is as follow,

                                      2 Na  +  F₂    →    2 NaF

As we know at Standard temperature and pressure 1 mole of ideal gases occupies 22.4 L of volume. Let us assume that in our case the Fluorine gas is acting ideally.

So, According to equation,

                   46 g (2mol) Na reacts with  =  22.4 L (1 mol) F₂

So,

                         32 g Na will react with  =  X L of F₂

Solving for X,

                    X  =  (32 g × 22.4 L) ÷ 46 g

                    X =  15.58 L of F₂

50.23 i believe is correct but don't quote me on that.