Given the two half-reactions, cr2o72- + 14 h+ + 6 e− imported asset 2 cr3+ + 7 h2o and h2c2o4 imported asset 2 co2 + 2 h+ + 2 e−, the next step you should take toward balancing the final equation is:

Two half reactions:

14H⁺ + Cr₂O₇²⁻+ 6e⁻ --> 2Cr³⁺ + 7H₂O (i)

H₂C₂O₄ --> 2CO₂(g) + 2H⁺ + 2e⁻ (ii)

To balance the equations, the next step is balance the number the electrons in both the reactions, by multiplying equation (ii) by 3.

(H₂C₂O₄ --> 2CO₂(g) + 2H⁺ + 2e⁻)×3

=(3H₂C₂O₄ --> 6CO₂(g) + 6H⁺ + 6e⁻)(iii)

Now second step is the addition of both the reactions.

14H⁺ + Cr₂O₇²⁻+ 6e⁻ --> 2Cr³⁺ + 7H₂O (i)

3H₂C₂O₄ --> 6CO₂(g) + 6H⁺ + 6e⁻(iii)

Balance equation:

Cr₂O₇²⁻ + 3H₂C₂O₄ + 8H⁺ > 2Cr³⁺ + 6CO₂(g) + 7H₂O

може ли да зареждате повече информация, моля

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.