Flag this question question 8 10 pts use the δh°f and δh°rxn information provided to calculate δh°f for if: δh°f (kj/mol) if7(g) + i2(g) → if5(g) + 2 if(g) δh°rxn = -89 kj if7(g) -941 if5(g) -840

Explanation

By definition,

Note, that iodine on the reactant side is stated as a gas in the equation given in the question whereas under standard conditions it is expected to be under the solid state; the given in the question seemingly corresponds to the one in which the reactant iodine exists as a solid rather than as a gas. Evaluating the last expression using data from an external source

(Cox, Wagman, et al., 1984)

... yields , which deviates significantly from the experimental value of (Chase, 1998.) It is thus assumed that the value provided requires a reaction with rather than as a reactant.