Gasoline and motor oil are chemically similar. they are both mixtures of nonpolar hydrocarbons containing carbon and hydrogen atoms. however, motor oil is much more viscous than gasoline. which substance probably has the higher average molar mass? answers: a. gasoline b. motor oil

Gasoline and motor oil are chemically similar. They are both mixtures of nonpolar hydrocarbons containing carbon and hydrogen atoms. However, motor oil is much more viscous Motor Oil

A chef is using honey in a recipe. The honey is too thick to pour out of the jar. How could the chef make the honey easier to pour? heat it

Water’s molar mass is 18.01 g/mol. The molar mass of methanol is 32.01 g/mol. At room temperature, water is 64% more viscous than methanol. Which substance has the stronger intermolecular attraction? water

B. Motor oil

Explanation:

Both gasoline and motor oil are non-polar hydrocarbons. The intermolecular force of attraction in these molecules is the London dispersion force which is higher for molecules with larger molar mass.

Viscosity  is essentially the resistance to flow offered by the liquid. This is dependent on the intermolecular force of attraction. Stronger force implies that the molecules are held together strongly and will not move freely resulting in higher viscosity.

It is given that motor oil is more viscous which implies that the molecules in motor oil are held by stronger intermolecular forces of attraction. This would suggest that motor oil would have a higher molar mass than gasoline.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied