Chemistry, 13.07.2019 11:30 valerieaj113

32. mercury has an atomic mass of 200.59 amu. calculate the a. mass of 3.0 x 1023 atoms. b. number of atoms in one nanogram of mercury? i needed on this question

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Answer from: zahradawkins2007

a.200.59 amu of mercury contains = 6.02 * 1023 molecules

Mass for 3.0 * 1023 molecules = (3.0 * 1023 * 200.59) /6.02 * 1023

= 100.29 amu

Thus, mass for 3.0 * 1023 molecules is 100.29 amu

b.As, 200.59 g mercury contains = 6.02 * 1023 atoms

1 g mercury contains = (6.02 * 1023 /200) atoms

= 3.01 * 1021 atoms

Thus, 1 ng mercury contains = (3.01 * 1021) / 109

= 3.01 * 1012 atoms

Thus, 3.0 * 1012 atoms present in 1 ng mercury

Answer from: devenybates

a) Mass of $3.0\times 10^{23} atoms$ of mercury is 99.91 g.

b) $3.0021\times 10^{12} atoms$ in 1 nano gram of mercury.

Explanation:

$Moles(n)=\frac{\text{mass of compound}}{\text{Molar mass of compound}}$

Number of molecules or number of atoms:

$n\times N_A$

$N_A=6.022\times 10^{23}$ atoms or molecules

Mercury has an atomic mass of 200.59 amu = 200.59 g/mol

Number of mercury atoms = $3.0\times 10^{23} atoms$

Moles of Mercury :

$\frac{3.0\times 10^{23} atoms}{6.022\times 10^{23}}=0.4981 moles$

Mass of 0.4981 moles of mercury:

0.4981 moles × 200.59 amu = 99.91 g

Mass of $3.0\times 10^{23} atoms$ of mercury is 99.91 g.

b) Mass of mercury = 1 nano gram = $10^{-9} g$

Moles of mercury: $\frac{10^{-9} g}{200.59 g/mol}$

Number of atoms of mercury in 1 nano gram:

: $\frac{10^{-9} g}{200.59 g/mol}\times 6.022\times 10^{23}$

$=3.0021\times 10^{12} atoms$

Answer from: Quest

it is important to conserve water because there is very limited amount of freshwater here on earth and if we are not smart about how we use it we will only be runnning out of our supply faster than neccessarry.

Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

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32. mercury has an atomic mass of 200.59 amu. calculate the a. mass of 3.0 x 1023 atoms. b. number o...

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