How many atoms of hydrogen are represented by the formula below? 4h2so4 a. 1 b. 4 c. 8 d. 28

2 atoms:

one mole is 6.022 times 10 to the 23 atoms according to Avogadro's Number, there are 2 Hydrogens in water, H20, so therefore 2 times 6.022 times to 10 to the 23 is your answer. O which means that ever molecule of water has 2 atoms of hydrogen (H) and one atom of oxygen (O)

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

c.

explanation: