What mass of sodium benzoate should be added to 160.0 ml of a 0.17 m benzoic acid solution in order to obtain a buffer with a ph of 4.30?

Answer :

The mass of sodium benzoate that can be added to benzoic acid is 5.07 g

Explanation :

The problem can be solved with the help of Henderson-Hasselbalch equation.

Step 1 : Find concentration of sodium benzoate

The equation is given below.

We have been given,

pH = 4.30

[Acid] = 0.17 M

Ka of benzoic acid can be found out using standard reference table which is 6.5 x 10⁻⁵

pKa = - log (Ka)

pKa = - log (6.5 x 10⁻⁵)

pKa = 4.19

Let us plug in the above values in Henderson equation.

The functions cancel out each other.

[Base] = 0.22 M

The base in this case is sodium benzoate.

Therefore concentration of sodium benzoate is 0.22 M.

Step 2 : Find moles of sodium benzoate

The volume of the solution is 160 mL.

Volume in L =

Moles of sodium benzoate can be found as,

Moles of sodium benzoate are 0.0352

Step 3 : Find mass of sodium benzoate

Mass of sodium benzoate can be calculated as

Mass in grams = Moles x Molar mass

The formula of sodium benzoate is C₇H₅O₂Na.

Molar mass of sodium benzoate = 7 x 12.01 + 5 x 1.01 + 2 x 16 + 22.98

Molar mass of sodium benzoate = 144.1

Mass of sodium benzoate =

Mass of sodium benzoate = 5.07 g

5.07 grams of sodium benzoate should be added to the given volume of benzoic acid.

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