Determine the ph of a solution that is 1.35% naoh by mass. assume that the solution has density of 1.01 g/ml.

-

13.545

Explanation: -

Let the volume of the solution be 1000 mL

Density = 1.04 g/ mL

Mass = density x vol

= 1.04 g/ mL x 1000 mL

= 1040 g

Amount of NaOH = x 1040 g

= 14.04 g

Molar mass of NaOH = 23 x 1 + 16 x 1 + 1 x 1

= 40 g / mol

Number of moles = Amount of NaOH / Molar mass

= 14.04 /40

= 0.351 mol

So 1000 ml of the solution has 0.351 mol

Molarity of NaOH = 0.351 M

Using the relation

pOH = - log [OH-]

= - log 0.351

= 0.455

Using the relation pH + pOH = 14

pH = 14 - pOH

= 14 - 0.455

= 13.545

zfoods? ok, pressure is used to keep the heat inside and to keep the food perfect.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml