Answers: 1
![pH = - log\:[H_3O^+]](/tpl/images/0086/2904/e3b0b.png)
![pH = - log\:[2*10^{-4}]](/tpl/images/0086/2904/78266.png)
![pH=-\log[H^+]](/tpl/images/0086/2904/cf945.png)
![[H^+]=1\times 2\times 10^{-4} M=2\times 10^{-4} M](/tpl/images/0086/2904/bade5.png)
![pH=-\log[2\times 10^{-4} M]=3.70](/tpl/images/0086/2904/844f2.png)
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