Reaction of hexamethylbenzene with methyl chloride and aluminum chloride gave a salt a, which, on being treated with aqueous sodium bicarbonate solution, yielded compound b. suggest a mechanism for the conversion of hexamethylbenzene to b by correctly inferring the structure of a

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The first step involves reaction of methyl chloride with AlCl₃.

Then the compound A generates by attack of pi bond on CH₃.

Then there is a rearrangement of the carbocation from 2° to 3°.

Finally a H⁺ is lost to give B

trigonal pyramidal

tetrahedral

trigonal planar

bent

? you expect us to answer this? ? this is your schoolwork, i don't think we can with this, i think it would considering being