Answers: 1
:
![K_{sp}=[Pb^{2+}][Cl^{-}]^{2}](/tpl/images/0086/6695/53ad1.png)
![[Cl^{-}] = 2.88 * 10^{-2} M](/tpl/images/0086/6695/a3584.png)
![[Pb^{2+}]=\frac{[Cl^{-}]}{2} = \frac{2.88 * 10^{-2}}{2}=1.44 *10^{-2}](/tpl/images/0086/6695/eaf65.png)
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Asaturated solution of pbcl2 is found to contain 2.88 x 10-2 m chloride ions. what is the correct va...
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