How much naoh is needed to prepare 461 ml of solution with a ph of 10.00?

The study of chemicals and bonds is called chemistry. There are different types of elements and these are metal and nonmetals.

The correct answer is

The data is given as follows:-

Using the relation pH + pOH = 14.00

pOH = 14.00 - 10.00= 4.00

Using the relation

[OH⁻] =

=  M

Since NaOH is a monobasic acid,

[NaOH] = [OH⁻] = M

Amount of NaOH = [NaOH] x Volume of NaOH

=   M x 0.461 L

= mol

The molar mass of NaOH =

Mass of NaOH required =

= 1.84 x 10⁻³ g

Hence, the correct answer is 1.84 x 10⁻³ g.

For more information about the ph, refer to the link:-

link

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Volume of NaOH = 461 mL = 461/1000 = 0.461 L

pH = 10.0

Using the relation pH + pOH = 14.00

pOH = 14.00 - 10.00= 4.00

Using the relation

[OH⁻] =

= M

Since NaOH is a monobasic acid,

[NaOH] = [OH⁻] = M

Amount of NaOH = [NaOH] x Volume of NaOH

= M x 0.461 L

= 4.61 x 10⁻⁵ mol

Molar mass of NaOH = 23 x 1 + 16 x 1 + 1 x1

= 40 g / mol

Mass of NaOH required = 4.61 x 10⁻⁵ mol x 40 g/ mol

= 1.84 x 10⁻³ g

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