Urgent! if a solution is made by dissolving 3.00 grams of magnesium chlorite into 30.0 grams of acetic acid (c2h4o2), what's the freezing point? (kf of acetic acid = 3.90 °c/m; freezing point of pure acetic acid = 16.6 °c)

Change in freezing point = Kf * (molality)* i

1) Kf for acetic acid = 3.90 C/molal

2) Molality = moles solute/kilograms

3.00 grams Mg(ClO2)2/ 30.0 g acetic acid x 1000 g/kg x 1mole Mg(ClO2)2 /159.2 grams = 0.628

3) i is the van’t hoff factor ;

Mg(ClO2)2 ; 24.3 + 2(35.45) + 4(16) = 159.2

Mg(ClO2)2 ==⇒ Mg2+ + 2ClO2-

The value of i is 3, since 3 ions are produced

Change in freezing point = 3.90 C/molal x 0.628 x 3 = 7.35 Celsius

Freezing point of solution = 16.6 – 7.35 = 9.3 Celsius

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

the correct answer is:

a. formation of precipitation