A569324 ml nacl solution is diluted to a volume of 1.33 l and a concentration of 4.87 m. what was the initial concentration? give the molar concentration rounded to the hundredths place without units.

Since 569324 mL = 569.324 L which is much more than 1.33 L that means it cannot be diluted to a volume of 1.33 L, so this must be 569.324 mL.

This question is solved by using the dilution equation which is :

Where = Initial concentration

= Initial volume

= Final concentration

= Final volume

In our question , the given information is : V1 = 569.324 mL

M2 = 4.87 M and V2 = 1.33 L and we need to find .

When we use dilution equation we need to make sure that both the units of volume have same units.

is in 'mL' and is in 'L' , so we will first convert into 'L'

=

= 0.569324 L

Now we will plug in the values of , in dilution equation and will calculate the value of .

(Initial concentration) = 11.38 M

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )