6h2s 6co2 6s0 glucose takes place under aerobic conditions. takes place under anaerobic conditions. the amount of oxygen does not make any difference.

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The reaction 6H₂S + 6CO₂ --light--> 6S0 + glucose takes place under anaerobic conditions

Explanation: -

The term anaerobic stands for does not use oxygen.

In the reaction given above

6H₂S + 6CO₂ --light--> 6S0 + glucose

We see that the reactants are hydrogen sulfide and carbon dioxide.

Thus oxygen is not being used in the reaction.

Hence the reaction is occurring under anaerobic conditions.

beta decay is the answer

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