What is the volume at stp of a sample that contains 4.00 x 10^23 molecules of methane, ch4?

We are given the #molecules (4.00x10^23) but we need moles so this is the formula we use

N= #molecules/6.02x10^23
4.00x10^23/6.02x10^23
N= 0.66

Now we can use the formula for STP
N=v/22.7
So we rearrange the formula like so;

V=nx22.7

V= 0.66 X 22.7
Therefore the volume equals
14.98L

I hope this helps

The reaction will shift to the right