How many grams of sodium can be reacted with 750 ml of a 6

The question is incomplete.

The complete question should be

How many grams of sodium can react with 750 mL of a 6.0 M solution of sulfuric acid, H₂SO₄?

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Strength of H₂SO₄ = 6.0 M

Volume of H₂SO₄ = 750 mL = 750/1000 = 0.75 L

Number of moles of H₂SO₄ = 0.75 L x 6.0 M

= 4.5 mole of H₂SO₄

The balanced chemical equation for this reaction is

2 Na + H₂SO₄ → Na₂SO₄ + H₂

From the balanced chemical equation we see

1 mole of H₂SO₄ react with 2 mole of Na

4.5 mole of H₂SO₄ react with mole of Na

= 9 mole of Na

Atomic mass of Na = 23 g/mol

Mass of Na = 9 mol x 23 g/ mol

= 207 g

Thus 207 grams of sodium can react with 750 mL of a 6.0 M solution of sulfuric acid, H₂SO₄