Agas at 250 k has a pressure of 0.00008 pa. if the pressure drops to 0.00002 pa, what is the new temperature? 500 k 1000 k 125 k 62.5 k

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If a gas at 250 K has a pressure of 0.00008 Pa and the pressure drops to 0.00002 Pa, 62.5 K is the new temperature

Explanation: -

Initial Pressure P₁ = 0.00008 Pa

Final Pressure P₂ = 0.00002 Pa

Initial Temperature T₁ = 250 K

Since the volume is not mentioned, it remains constant.

So initial Volume V₁ = Final volume V₂

Now using the combined gas equation

=

Final Temperature T₂ =

Plugging in the values,

T₂ =

As V₂ = V₁, they cancel each other.

T₂ = 62.5 K

i belive it is water