What is the molality of a solution prepared by dissolving 82.2 g of ethylene glycol, hoch2ch2oh, in 1.50 l of water? assume the density of water is 1.00 g/ml?

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0.883 m

Explanation:-

Molality= Moles per Kg of solvent.

Molar mass of ethylene glycol= 62.07 g/ mol.

Number of moles of ethylene glycol= 82.2g / (62.07 g/mol)

= 1.324 moles

Density of water = 1 g/ml = (1/1000kg)/ (1/1000litre)

= 1 Kg / litre

Mass of 1.5 litre of water = 1.5 litre x 1 kg / litre

= 1.5 kg

Molality of ethylene glycol = 1.324 moles/1.5 kg

= 0.883 m

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