For the reaction below, the equilibrium concentrations were found to be [nh3] = 0.250 m ; [h2] = 0.420 m ; [n2] = 0.800 m . give the equilibrium constant expression and use it to calculate the constant. 2 nh3(g) 3 h2(g) + n2(g)

Equation for the decomposition of ammonia :

2NH3->N2+3H2

Equilibrium constant for this equation will be:

Kc=[N2]([H2]^3)/[NH3]^2

As given Concentration of N2=0.800 M

Concentration of H2=0.420 M

Concentration of NH3=0.250 M

So Kc=([0.420]^3) *(0.8)/([0.250]^2)

= 0.9483264

so equilibrium constant will be:

0.9483264

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24