When the volume of a gas is changed from 1145 ml to 765 ml, the temperature will change from ? k to 640 k?

The answer is: T1 = 957.91K

Explanation:

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Let's solve this!

The data we have are:

V1: 1145ml

V2: 765ml

T2: 640K

From the equation of the ideal gas, we have that the pressure is the same, the constant of the gases R is the same and the number of moles is the same.

We match the equations and we have:

V1 / T1 = V2 / T2

We have to find out T1:

T1 = (V1 * T2) / V2

T1 = (1145ml * 640K) / 765ml

T1 = 957.91K

The answer is: T1 = 957.91K

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