Starting with solid kcl and water, how many grams of kcl are needed to prepare 3.00 liters of a 2.00 m kcl solution?

One mol of KCl (potassium chloride) is 74.5 gram  (molar mass is 74.5 gram/mol).
First, let's calculate the total number of moles in this solution:
n = C * V = 2 Mol/L  * 3 L = 6 mol

Then we convert to gram
1 mol ==> 74.5 gram
6 mol ==> 74.5 * 6 = 447 gram of KCl

To prepare 3 liters of 2M KCl solution, you need to dissolve 447grams of KCl in 3 liters of distilled water.

Spontaneity tell us the direction of the reaction, but not how fast it goes. gibbs free energy brings together enthalpy, entropy and temperature in one easy formula. g = h - ts. and, finally the sign of delta g is always negative for a spontaneous reaction.

Woah that’s a lot to read xd i’ll try though. i’ll get back t you if. i know the andwer