Aspecimen weighing 100.0 g is heated from 30.00°c to 63.30°c. if the quantity of heat transferred is 5834 cal, determine the specific heat of the specimen.

Answer : 1.752 cal/ g °C

Explanation : Given information ;

Weight of sample - 100 g; Temperature initial - 30.0 Temperature final - 63.30

specific heat transferred - 5834 cal

On solving we get, (5834 cal) / (100 g) / (63.3 -30.0) = 1.752 cal/g°C