Rubbing alcohol is 70.% (m/v) isopropyl alcohol by volume. how many ml of isopropyl alcohol are in a 1 pint (473 ml) container?

 The number  of ml of isopropyl  alcohol  that are 1 pint (473 Ml)   is  331.1 Ml

   calculation
 
assume  that  the 1 pint  is in  a  container

   This implies  that the 1 pint (473 ml)  is  in 100 %  M/V
      what about 70 %(M/V)

 that is  473 Ml  = 100 %
                   ?   =   70 %

by  cross  multiplication
    =  473 x70/100 = 331.1 Ml

There are 331.10 milliliters of isopropyl alcohol are in a 1 pint (473 ml) container.

Since rubbing alcohol is 70% (m / v) isopropyl alcohol by volume, to determine how many ml of isopropyl alcohol are in a 1 pint (473 ml) container, the following calculation must be performed:

473 x 70/100 = X 473 x 0.7 = X 331.1 = X

Therefore, there are 331.10 milliliters of isopropyl alcohol are in a 1 pint (473 ml) container.

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What is the question

7is b8 is d9 is c10 is a11 is d