You are a scientist working on increasing the efficiency of appliances to waste less electricity. you are running experiments measuring the input, output, and waste energy from a new type of light source. given the data below, determine the percentage of energy transformed into light. 25978.8 joules in, 14153.3 joules wasted, 11825.5 joules out a. 45.5% b. 54.5% c. 11825.5% d. 83.5%

Answer : Option A) 45.5%
 
Explanation : We use the formula of calculating energy efficiency which is as,

η (in %)= [] X 100 
where η is energy efficiency,
and P values are for energy out and in.

So plugging the given values, we get,

η (in %) = (11825.5 / 25978.8) X 100 = 45.5 %

Electron equations of the given changes are as follow,a)                              cu      →      cu⁺²  + 2e⁻b)                              mg⁺²  +  2 e⁻      →      mgc)                              cl⁻    →      cl  +  1e⁻d)                              s  +  2 e⁻    →      s²⁻e)                                o²⁻      →      o  +  2 e⁻f)                              p  +  3 e⁻    →      p³⁻g)                              fe²⁺    →      fe³⁺  + 1 e⁻h)                              s²⁻    →      s⁴⁺  +  6 e⁻

I'm pretty sure its the solar eclipse.