In the reaction h2so4 + 2 naoh -> na2so4 + 2h2o, an equivalence point occurs when 23.1 ml of 0.2055 m naoh is added to a 25.0 ml portion of h2so4. what is the [h2so4]?

            moles NaOH = c · V = 0.2055 mmol/mL · 23.1 mL = 4.74705 mmol
            moles H2SO4 = 4.74705 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 2.373525 mmol
Hence
            [H2SO4]= n/V = 2.373525 mmol / 25.0 mL = 0.09494 M
The answer to this question is  [H2SO4] = 0.09494 M