What is the percent yield of h2o if 87.0 g of h2o is produced by combining 95.0 g of o2 and 11.0 g of h2

The percent yield of water is 87.87%.

Explanation:

Experimental yield of water =  87.0 g

Theoretical yield of water will be calculate as:

Moles of oxygen gas :

Moles of hydrogen gas:

2 moles of hydrogen reacts with 1 mole of oxygen then, 5.5 moles of hydrogen will react with 2.75 moles of oxygen gas.

Hydrogen gas is in limited amount hence will act as limiting reagent in the reaction.

According to reaction, 2 moles of hydrogen reacts gives 2 mole of water

Then, 5.5 moles of hydrogen gas will give:

of water

Theoretical yield of water = 5.5 × 18 g/mol=99 g

Percentage yiled:

The percent yield of water is 87.87%.

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

particle   p is an electron and particle q is a neutron