In the combustion of ethane, shown above, how many moles of carbon dioxide can be produced from 1.00 mole of ethane? a. 0.500 mole b. 1.00 mole c. 2.00 moles d. 4.00 moles

The balanced chemical equation for the combustion of ethane is 
2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l)

The stoichiometric ratio between C₂H₆(g) and CO₂(g)  is 1 : 2

Hence,
    moles of CO₂(g) produced = moles of reacted C₂H₆(g) x 2
                                                  = 1.00 mol x 2
                                                  = 2.00 mol

Hence, the correct answer is "C".

Woah that’s a lot to read xd i’ll try though. i’ll get back t you if. i know the andwer