Iwill give brainliest asap show all work on this problem. which solution will have a higher boiling point: a solution containing 15 grams of sucrose (c12h22o11) in 25 grams of water or a solution containing 35 grams of sodium chloride in 500 grams of water?

The answer is sodium chloride solution

Boiling point will increase based on the molality(mol per 1000gram solution) of the solution. The exact value formula should be: T= i * Kb * molality
Kb is the constant of the solvent(water) and i is the Van Hoff factor of the solute.

The molecular mass of sucrose is 342g/mol. The increase of boiling point for sucrose  solution is: 
T= i * Kb * molality
T= i * Kb * mol / (solvent/ 1000g)
T= 1 * Kb * 15grams/(342grams/mol) / (25gram1000g)
T= 1 * Kb * 0.043mol / 0.025
T= 1.7643 Kb

The molecular mass of sodium chloride is 58.5g/mol and its van hoff factor is 2(it dissolve into Na+ and Cl-). The increase of boiling point for sucrose  solution is: 
T= i * Kb * molality
T= i * Kb * mol / 1kg solvent
T= 2 * Kb * 35grams/(58.5g/mol) / (500g/1000g)
T= 2 * Kb * 0.598mol / 0.5
T= 2.3931 Kb

Mgo2 is the oxidation state of manganese oxide