Chemistry, 17.07.2019 05:00 soulspiritsa

For the chemical reaction hclo4(aq)+naoh(aq)⟶h2o(l)+naclo4(aq ) write the net ionic equation, including the phases.

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The net ionic equation is as below

H^+(aq) + H^-(aq) → H2O(l)

Explanation
from the chemical equation

HClO4(aq) + NaOH (aq) → H2O(l) + NaClO4(aq)

write ionic equation
that is,
H^+(aq)+ClO4^-(aq) + Na^+(aq) +OH^-(aq)→ H2O(l) + Na^+(aq)+ClO4^-(aq)

cancel the spectator ions in both side(ions that do no take place in a chemical equation)
that ClO4^- and Na^+

the net ionic is therefore
= H^+(aq) + OH^-(aq) → H2O(l)

Answer from: 19wawrzkeek

The net ionic equation is defined as the removing spectator ions from total equation and list the species that only participate in the reaction. In the given equation, $\text {HClO}_{4}_{(aq)}+\text{NaOH}_{(aq)}\rightarrow\text{H}_{2}\text O_{(l)}+\text {NaClO}_{4}_{(aq)}$ , the net iconic equation will be:

$H^{+}_{(aq)} + \text{OH}^{-}_{(aq)}\rightarrow \text{H}_{2}\text{O}_{(l)}$

In aqueous solution, HClO $_{4}$ will dissolve into H $^{+}$ and ClO $_{4}^{-}$ . Similarly, NaOH will be dissociated into Na $^{+}$ and OH-. The resultant salt formed is NaClO $_{4}$ . The equation can be expanded as:

$\text {HClO}_{4}_{(aq)}+\text{NaOH}_{(aq)}\rightarrow\text{H}_{2}\text O_{(l)}+\text {NaClO}_{4}_{(aq)}\\\\\text {H}^{+} + \text {ClO}_{4}^{-} + \text {Na}^{+} + \text {OH}^{-}\rightarrow \text{H}_{2}\text {O} + \text{Na}^{+}+ \text {ClO}_{4}^{-}$

Thus, cancelling out the terms on both sides of the equation, those are termed as spectator ions. The spectator ions are:

$\text {H}^{+} + \text {ClO}_{4}^{-} + \text {Na}^{+} + \text {OH}^{-}\rightarrow \text{H}_{2}\text {O} + \text{Na}^{+}+ \text {ClO}_{4}^{-}$

Remaining, net iconic equation is:

$H^{+}_{(aq)} + \text{OH}^{-}_{(aq)}\rightarrow \text{H}_{2}\text{O}_{(l)}$

Therefore, for any strong acid and strong basic reaction, the net ionic reaction is the neutralization of Hydrogen and Hydroxide ions to form water.

To know more net iconic equations, refer to the following link:

link

Answer from: Quest

Is there a diagram/picture you can provide? it seems this question goes along with a

Answer from: Quest

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

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For the chemical reaction hclo4(aq)+naoh(aq)⟶h2o(l)+naclo4(aq ) write the net ionic equation, includ...

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