Calculate the number of joules released when 0.64 grams of steam (c = 2.04 l/g c. are cooled from 125 c to 105 c it is okay to have negative values

The number  of  joules  released  when  0.64g  of   steam  are  cooled  from 125 c  to 105  c is  -26.112  joules

      calculation
by  use of Q=MCΔ T  formula  calculate the  joules released  where
Q( heat) =?
M (mass) =  0.64 g
C (specific heat capacity = 2.04 j/g/c
ΔT(change  in temperature) =  105-125 =-20c

Q  is  therefore = 0.64 g   x2.04 j/g/c x -20  c = -26.112  joules

it  is okay  to have negative value  since  the  reaction   is exothermic that  is heat  is  released