How many moles of gas are present in a 1.07 l sample at 1.56 atm and a temperature of 22.0oc?

Answer is: 0.069 moles of of gas are present.

V(gas) = 1.07 L; volume.
T = 22.0°C = 295.15 K; temperature of gas.
p = 1.56 atm; pressure of gas.
R = 0.08206 L·atm/mol·K; gas constant.
Ideal gas law: p·V = n·R·T.
n = p·V / R·T.
n(gas) = 1.56 atm · 1.07 L / 0.08206 L·atm/mol·K · 295.15 K.
n(gas) = 0.069 mol; amount of substance.

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