If the mole fraction of k2so3 in an aqueous solution is 0.0328 what is the weight/weight % of k2so3

Explanation:

Hello,

In this case, since potassium sulfite is in an aqueous solution, that is water as solvent, one could assume 0.0328 moles of potassium sulfite and 1 mole of solution (total), therefore, the moles of water are:

Thus, one calculates each compound's grams by using their molar masses as:

Therefore, its weight/weight % turns out:

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c8h10 is your answerr

aquifers are bounded above and below by impermeable rock. the driving force of groundwater movement in confined aquifers is pressure, rather than gravity.